For this we need to use a few equations (it is best to show with an example)...
Calculate the volume of carbon dioxide produced when 50g of calcium carbonate is decomposed by heating.
Step 1 - Calculate the amount, in moles, of calcium carbonate reacted
work out the Mr of CaCO... it's 100
Therefore, we can work out the amount, in moles, of calcium carbonate that was reacted...
Amount, in moles, of CaCO₃ = (50 ÷ 100) = 0.5 mol
Step 2 - Calculate the amount, in moles, of carbon dioxide formed
CaCO₃ ------> CaO + CO₂
1 mol of CaCO₃ produces 1 mol of CO₂, therefore, 0.5 mol of CaCO₃ must produce 0.5 mol of CO₂
Step 3 - Calculate the volume of CO₂ formed
Volume of CO₂ (in dm3) = (0.5 x 24) dm³ = 12dm³
So, the volume of carbon dioxide produced when 50g of calcium carbonate is decomposed by heating, is 12dm3
A blog covering and explaining the Edexcel IGCSE Chemistry specification for the 2016 summer exams. If you are doing just double science, you do not need to learn the stuff for paper two, if you are doing triple you will need to learn all (GOOD LUCK!) I have separated the papers to make files easier to find. Hope it helps :)
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment