Saturday, 23 April 2016

5.3 write ionic half-equations for the reactions at the electrodes in aluminium extraction.

If you are looking at this post I assume you know what the electrolysis of aluminium oxide is and the implications, if you do not know, this may help... 5.2

 The equations are as follows...

 At the anode (positive electrode): 2O2− ---> O2 + 4e− 

At the cathode (negative electrode): Al3+ + 3e− ---> Al
at

2 comments:

  1. Anonymous9 February 2017 at 00:22

    The right equation for cathode (negative electrode) is : Al3+ + 3e- → Al

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    Replies
    1. Millie20 April 2017 at 12:39

      Good spot thank you!! mustve just been a typo hahaha, will change it now:)

      Delete